An equation is almost a sort of seesaw: you add something to the left, lose the balance and are forced to do the same to the right; you divide and multiply by something, once again,
the same must be done to the other side; if you subtract something, there is no exception. Therefore, solving equation means, getting rid of everything around *x* by *seesaw* method.

**E.g.1**

x + 5 = 8

- 5 => x + 5 -5 = 8 - 5

x = 3

**E.g.2**

x - 5 = 10

+ 5 => x -5 + 5 = 10 + 5

x = 15

**E.g.3**

2x = 10

:- 2 => 2x / 2 = 10 /2

x = 5

**E.g.4**

x / 5 = 2

X 5 => x /5 X 5 = 2 X 5

x = 10

**E.g.5**

2x - 4 = 10

+ 4 => 2x - 4 + 4 = 10 + 4

2x = 14

:- 2 => 2x / 2 = 14 / 2

x = 7

**E.g.6**

2x + 4 = 10

- 4 => 2x + 4 - 4 = 10 - 4

2x = 6

:- 2 => 2x / 2 = 6 / 2

x = 3

**E.g.7**

x/3 + 7 = 10

-7 => x/3 + 7 - 7 = 10 - 7

x/3 = 3

X 3 => x/3 X 3 = 3 X 3

x = 9

**E.g.8**

(x - 3) / 4 = 3

X 4 => (x-3) /4 X 4 = 3 X 4

(x-3) = 12

+ 3 => x - 3 + 3 = 12 + 3

x = 15

**E.g.9**

3x + 3 = x + 10

-3 => 3x + 3 -3 =x + 10 - 3

3x = x + 7

- x => 3x - x = x - x + 7

2x = 7

:-2 => 2x / 2 = 7 / 2

x = 3.5

**E.g.10**

2x - 4 = 5x + 8

+4 => 2x - 4 + 4 = 5x + 8 + 4

2x = 5x + 12

-5x => 2x - 5x = 5x - 5x + 12

-3x = 12

:--3 => -3x/-3 = 12 / -3

x = -4

With this simple programme, you can generate questions at random, along with answers - unlimited number of questions. Generate the question first, work out the solution and then check with the answer shown below the question.

Maths is challenging; so is finding the right book. K A Stroud, in this book, cleverly managed to make all the major topics crystal clear with plenty of examples; popularity of the book speak for itself - 7^{th} edition in print.